14x^2-15x-11=0

Solution for 14x^2-15x-11=0 equation:

14x^2-15x-11=0

a = 14; b = -15; c = -11;
Δ = b2-4ac
Δ = -152-4·14·(-11)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-29}{2*14}=\frac{-14}{28}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+29}{2*14}=\frac{44}{28}
=1+4/7
$